rust-by-practice/en/src/formatted-output/debug-display.md

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# Debug and Display
All types which want to be printable must implement the `std::fmt` formatting trait: `std::fmt::Debug` or `std::fmt::Display`.
Automatic implementations are only provided for types such as in the `std` library. All others have to be manually implemented.
## Debug
The implementation of `Debug` is very straightfoward: All types can `derive` the `std::fmt::Debug` implementation. This is not true for `std::fmt::Display` which must be manually implemented.
`{:?}` must be used to print out the type which has implemented the `Debug` trait.
```rust
// This structure cannot be printed either with `fmt::Display` or
// with `fmt::Debug`.
struct UnPrintable(i32);
// To make this struct printable with `fmt::Debug`, we can derive the automatic implementations provided by Rust
#[derive(Debug)]
struct DebugPrintable(i32);
```
1. 🌟
```rust,editable
/* Fill in the blanks and Fix the errors */
struct Structure(i32);
fn main() {
// Types in std and Rust have implemented the fmt::Debug trait
println!("__ months in a year.", 12);
println!("Now __ will print!", Structure(3));
}
```
2. 🌟🌟 So `fmt::Debug` definitely makes one type printable, but sacrifices some elegance. Maybe we can get more elegant by replacing `{:?}` with something else( but not `{}` !)
```rust,editable
#[derive(Debug)]
struct Person {
name: String,
age: u8
}
fn main() {
let person = Person { name: "Sunface".to_string(), age: 18 };
/* Make it output:
Person {
name: "Sunface",
age: 18,
}
*/
println!("{:?}", person);
}
```
3. 🌟🌟 We can also manually implement `Debug` trait for our types
```rust,editable
#[derive(Debug)]
struct Structure(i32);
#[derive(Debug)]
struct Deep(Structure);
fn main() {
// The problem with `derive` is there is no control over how
// the results look. What if I want this to just show a `7`?
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/* Make it print: Now 7 will print! */
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println!("Now {:?} will print!", Deep(Structure(7)));
}
```
## Display
Yeah, `Debug` is simple and easy to use. But sometimes we want to customize the output appearance of our type. This is where `Display` really shines.
Unlike `Debug`, there is no way to derive the implementation of the `Display` trait, we have to manually implement it.
Anotherthing to note: the placefolder for `Display` is `{}` not `{:?}`.
4. 🌟🌟
```rust,editable
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/* Make it work*/
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use std::fmt;
struct Point2D {
x: f64,
y: f64,
}
impl fmt::Display for Point2D {
/* Implement.. */
}
impl fmt::Debug for Point2D {
/* Implement.. */
}
fn main() {
let point = Point2D { x: 3.3, y: 7.2 };
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assert_eq!(format!("{}",point), "Display: 3.3 + 7.2i");
assert_eq!(format!("{:?}",point), "Debug: Complex { real: 3.3, imag: 7.2 }");
println!("Success!")
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}
```
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### `?` operator
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Implementing `fmt::Display` for a structure whose elements must be handled separately is triky. The problem is each `write!` generates a `fmt::Result` which must be handled in the same place.
Fortunately, Rust provides the `?` operator to help us eliminate some unnecessary codes for deaing with `fmt::Result`.
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5. 🌟🌟
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```rust,editable
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/* Make it work */
use std::fmt;
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struct List(Vec<i32>);
impl fmt::Display for List {
fn fmt(&self, f: &mut fmt::Formatter) -> fmt::Result {
// Extract the value using tuple indexing,
// and create a reference to `vec`.
let vec = &self.0;
write!(f, "[")?;
// Iterate over `v` in `vec` while enumerating the iteration
// count in `count`.
for (count, v) in vec.iter().enumerate() {
// For every element except the first, add a comma.
// Use the ? operator to return on errors.
if count != 0 { write!(f, ", ")?; }
write!(f, "{}", v)?;
}
// Close the opened bracket and return a fmt::Result value.
write!(f, "]")
}
}
fn main() {
let v = List(vec![1, 2, 3]);
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assert_eq!(format!("{}",v), "[0: 1, 1: 2, 2: 3]");
println!("Success!")
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}
```